Question

At a certain temperature, oxygen molecules have an average speed of 460.7 m/s. What is the speed of helium atoms at the same conditions?

Answer 1

root mean square velocity is \[V=\sqrt{3RT/M}\]
THEREFORE...
\[V _{OXYGEN}^2 *M_{OXYGEN}=V _{HYDROGEN}^2 *M_{HYDROGEN}\]
BY \[(460.7^2*32)/2=V_{HYDROGEN}^2\]
\[V_{HYDROGEN}=2606 m/s\]