Question

Alg 2 b help??

Answer 1

question?

Answer 2

shay!

Answer 3

hello @dan815 and @aubreyk9616 what is the question ?

Answer 4

Question question please~

Answer 5

please post the question

Answer 6

you have to post the question so we can help...

Answer 7

3. write an equation for the translation of y=6/x that has the asymptotes x=4 and y=5

Answer 8

the original eqn is \[xy=6\] whose asymptotes are x=0 and y=0
shifting the asymptotes to x=4 and y=5
we need to shift the eqn to right by 4 units and upwards by 5 units
hence the eqn becomes....
\[\left(x-4\right)\left(y-5\right)=6\]

Answer 9

Awesome that's what I got

Answer 10

good luck

Answer 11

Do you know this one ??
What is the 20th term of the sequence that begins -4, 8,-16,32

Answer 12

2097152

Answer 13

Awesome thank you so much sweetie :)
can you halp me with one more

Answer 14

\[(-1)^n(2)^{n=1}\]

Answer 15

n+1***

Answer 16

it is geometric sequence which has a common ratio of -2
therefore... \[An=ar^\left( n-1 \right)\]
where : An is any 'n'th term , 'a' is the first term and 'r' is the common ratio
therefore...eqn comes \[A _{20}=(-4)*(-2)^{19}\]
which is 2097152

Answer 17

The 5th term in a geometric sequence is 140. the 7th term is 35. What are the possible values of the 6th term of the sequence

Answer 18

if three number,say, a,b,c are in gp

then c/b=b/a
this is how u caluclate the common ratio
if u simplify ...u get \[b ^{2}=ac\]
therefore... in this question...
a=140
c=35
therefore \[b ^{2}=140*35=4900\]
therefore b= sixth term=70