Mathematics
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OpenStudy (anonymous):
In circle O, PA and PB are tangents.
a. Prove that triangle APO is congruent to triangle BPO.
b. Find BOD for AOP=64 degrees. Explain your reasoning.
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OpenStudy (anonymous):
ganeshie8 (ganeshie8):
@Shay17
ganeshie8 (ganeshie8):
she worked these yesterday^
OpenStudy (dan815):
shay likes to play chess
OpenStudy (anonymous):
it is congruent by SSS
oa=ob=radius
op=op=common line
ap=bp=tangents from apoint to a circle are equal in length
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OpenStudy (dan815):
ganeshi we have another contender
OpenStudy (anonymous):
contender? @dan815
OpenStudy (dan815):
ah nothing i meant to play chess
OpenStudy (anonymous):
I am very confused
OpenStudy (anonymous):
Like she answered or asked them @ganeshie8
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OpenStudy (anonymous):
Um ok dan
OpenStudy (anonymous):
Can anyone help me?
ganeshie8 (ganeshie8):
lol really, ashley ?
OpenStudy (anonymous):
What?
ganeshie8 (ganeshie8):
she did all ur problems yesterday, if u r nice to @Shay17 ... she may help u wid all the problems :)
anyways let me work this problem wid u
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OpenStudy (dan815):
=O
OpenStudy (anonymous):
Uh, okay
OpenStudy (dan815):
i am very disappointed in you ashley
OpenStudy (dan815):
this is why the rod should not be spared
OpenStudy (anonymous):
sure i'll help what question is this ?
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OpenStudy (anonymous):
In circle O, PA and PB are tangents.
a. Prove that triangle APO is congruent to triangle BPO.
b. Find BOD for AOP=64 degrees. Explain your reasoning.
OpenStudy (anonymous):
do you go to james madison high school ? @ashley137
OpenStudy (anonymous):
No.... Why?
OpenStudy (anonymous):
ok well i would have to look for the question
@ganeshie8 just help her with this one
OpenStudy (dan815):
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