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Mathematics 19 Online
OpenStudy (anonymous):

In circle O, PA and PB are tangents. a. Prove that triangle APO is congruent to triangle BPO. b. Find BOD for AOP=64 degrees. Explain your reasoning.

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

@Shay17

ganeshie8 (ganeshie8):

she worked these yesterday^

OpenStudy (dan815):

shay likes to play chess

OpenStudy (anonymous):

it is congruent by SSS oa=ob=radius op=op=common line ap=bp=tangents from apoint to a circle are equal in length

OpenStudy (dan815):

ganeshi we have another contender

OpenStudy (anonymous):

contender? @dan815

OpenStudy (dan815):

ah nothing i meant to play chess

OpenStudy (anonymous):

I am very confused

OpenStudy (anonymous):

Like she answered or asked them @ganeshie8

OpenStudy (anonymous):

Um ok dan

OpenStudy (anonymous):

Can anyone help me?

ganeshie8 (ganeshie8):

lol really, ashley ?

OpenStudy (anonymous):

What?

ganeshie8 (ganeshie8):

she did all ur problems yesterday, if u r nice to @Shay17 ... she may help u wid all the problems :) anyways let me work this problem wid u

OpenStudy (dan815):

=O

OpenStudy (anonymous):

Uh, okay

OpenStudy (dan815):

i am very disappointed in you ashley

OpenStudy (dan815):

this is why the rod should not be spared

OpenStudy (anonymous):

sure i'll help what question is this ?

OpenStudy (anonymous):

In circle O, PA and PB are tangents. a. Prove that triangle APO is congruent to triangle BPO. b. Find BOD for AOP=64 degrees. Explain your reasoning.

OpenStudy (anonymous):

do you go to james madison high school ? @ashley137

OpenStudy (anonymous):

No.... Why?

OpenStudy (anonymous):

ok well i would have to look for the question @ganeshie8 just help her with this one

OpenStudy (dan815):

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