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Chemistry 16 Online
OpenStudy (anonymous):

The NaHCO3 is the limiting reactant and the HCl is the excess reactant in this experiment. Determine the theoretical yield of the NaCl product, showing all of your work in the space below.

OpenStudy (anonymous):

OpenStudy (aaronq):

use the moles of the limiting reactant to find the moles of NaCl with a ratio of their coefficients (from the balanced reaction). Set it up like this: \(\dfrac{moles~of~NaHCO_3}{NaHCO_3's~ coefficient}=\dfrac{moles~of~NaCl}{NaCl's ~coefficient}\) then solve for moles of NaCl, like algebra. For example, \(\dfrac{2}{3}=\dfrac{x}{4}\rightarrow x=\dfrac{4*2}{3}\)

OpenStudy (anonymous):

How do I find the moles

OpenStudy (somy):

mole= mass/ Mr

OpenStudy (somy):

u have masses so find Mr of each solution then use that formula

OpenStudy (anonymous):

What's mr?

OpenStudy (aaronq):

molar mass

OpenStudy (anonymous):

Okay so how do find that

OpenStudy (somy):

ok look u have ur periodic table ryt?

OpenStudy (anonymous):

yeah

OpenStudy (somy):

NaHCO3 so from periodic table find masses of Na, H, C, O then add them up, since there are 3 oxygens that means that mass *3 and only then add those numbers up

OpenStudy (somy):

do same thing with HCl

OpenStudy (somy):

make sure to subtract mass of the dish from ur given values

OpenStudy (anonymous):

Is molar mass the same thing as mass?

OpenStudy (somy):

not really, molar mass is in amu

OpenStudy (somy):

sorry i can explain all the work in steps to make it easy for you, but im outside right now, i'll be back only like in 3-4 hours T_T

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