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Meta-math 16 Online
ganeshie8 (ganeshie8):

@No.name

OpenStudy (anonymous):

yes?

ganeshie8 (ganeshie8):

you're claiming \(\sum \limits_{n=1}^{\infty} \dfrac{n^k}{B^n} = \dfrac{B(B+1)(B+2)\cdots (B+k)}{(B-1)^{k+1}} \) right ?

ganeshie8 (ganeshie8):

please correct the formula if it doesnt look right :)

OpenStudy (anonymous):

I don't quite understand these notations still. But i found one site which u could see http://nealabq.com/blog/category/analysis/

OpenStudy (anonymous):

Although my professor told these formulaes long back . i took time to recall them

ganeshie8 (ganeshie8):

nice :) that link says for n>=3 the pattern wont match the numerator !

OpenStudy (anonymous):

oh i see!

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