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Chemistry 9 Online
OpenStudy (anonymous):

calculate the molarity of a BaOH2 solution if 1900 mL is completely titrated by 261 mL of 0.505 M HNO ---- PLEAS HELP

OpenStudy (somy):

first of all write a balanced equation between BaOH2 and HNO3

OpenStudy (somy):

then you have molarity and volume of HNO3 so find mole using molarity= mole/ volume thus mole= molarity * volume

OpenStudy (somy):

then after u find the mole, look at the ratio between Ba(OH)2 and HNO3 then according to that ratio u can find mole of Ba(OH)3 then use molarity= mole/ volume since u'll find mole and u already have volume now u can find molarity of Ba(OH)2

OpenStudy (somy):

if its not clear let me know i'll show with numbers, but i hope u get it :)

OpenStudy (somy):

btw its HNO or HNO3? well whatever that is u still do same working :)

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