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Mathematics 11 Online
OpenStudy (anonymous):

Help solve for two angles and missing side length

OpenStudy (anonymous):

Well what are they haha

OpenStudy (anonymous):

|dw:1401229177482:dw|

OpenStudy (anonymous):

Which sides exactly?

OpenStudy (anonymous):

side b and c

OpenStudy (anonymous):

|dw:1401229311220:dw|

OpenStudy (anonymous):

Well first off, let's see if we can do this the easy way an solve using our trig function. Could sin cos or tan work here?

OpenStudy (anonymous):

yes im just not sure which on, I don't think it is tan

OpenStudy (anonymous):

@jdoe0001 could you maybe help with this, you have helped me in the past and you explain things really well

OpenStudy (jdoe0001):

I assume you've covered the Law of Cosines already?

OpenStudy (anonymous):

yes I have I just need a refresher on how to set up the equations to solve this

OpenStudy (jdoe0001):

|dw:1401230752134:dw| \(\bf \textit{Law of Cosines}\\ \quad \\ b^2 = {\color{blue}{ a}}^2+{\color{red}{ c}}^2-(2{\color{blue}{ a}}{\color{red}{ c}})cos(B)\implies b = \sqrt{{\color{blue}{ a}}^2+{\color{red}{ c}}^2-(2{\color{blue}{ a}}{\color{red}{ c}})cos(B)} \\ \quad \\ b = \sqrt{{\color{blue}{ 8}}^2+{\color{red}{ 5}}^2-(2\cdot {\color{blue}{ 8}}\cdot {\color{red}{ 5}})cos(20^o)}\)

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