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OpenStudy (anonymous):
The position of an object at time t is given by s(t) = -4 - 2t. Find the instantaneous velocity at t = 6 by finding the derivative.
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OpenStudy (anonymous):
(f(a+h) - f(a)) / h
OpenStudy (anonymous):
the velocity is ds/dt. So, differentiate s(t) to get v(t) and then plug the value of t in the expression.
OpenStudy (anonymous):
how do i differentiate?
OpenStudy (anonymous):
\[\frac{ f(a+h) -f(a) }{ h}\]
OpenStudy (anonymous):
I don't think that makes any sense, which one would be f,a and h?
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OpenStudy (anonymous):
when you differentiate the constant term will vanish. Any term like \[cx^n\] will become \[ncx^{n-1}\]. Thus 2t will become \[1.2.t^0 = 2.1 = 2\]
OpenStudy (anonymous):
So once we differntiate, I just add/subtract and that'll be my answer?
OpenStudy (anonymous):
yes.
OpenStudy (anonymous):
rkopen has given you the shortcut to solving this problem. Do you understand
OpenStudy (anonymous):
-4-2 = -6
So -6 is my derivative, correct?
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OpenStudy (anonymous):
No -4 term will become 0 since 4 is a constant.
OpenStudy (anonymous):
0-2=-2?
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