David kicks a soccer ball off the ground and in the air with an initial velocity of 35 feet per second. Using the formula H(t) = -16t2 + vt + s, what is the maximum height the soccer ball reaches?
17.9 feet
18.2 feet
18.7 feet
19.1 feet
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OpenStudy (anonymous):
@jim_thompson5910 @jdoe0001
jimthompson5910 (jim_thompson5910):
what are v and s in that equation?
OpenStudy (anonymous):
umm I think the v is 35, i might be wrong tho
jimthompson5910 (jim_thompson5910):
v = 35 is correct
what is s
OpenStudy (anonymous):
im not sure
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jimthompson5910 (jim_thompson5910):
s is the initial or starting height of the ball
OpenStudy (anonymous):
which is 0?
jimthompson5910 (jim_thompson5910):
v = 35
s = 0
yep
jimthompson5910 (jim_thompson5910):
so the equation is
\[\Large H(t) = -16t^2 + 35t + 0\]
and that turns into
\[\Large H(t) = -16t^2 + 35t\]
OpenStudy (anonymous):
ok now do I factor it?
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jimthompson5910 (jim_thompson5910):
How would you find the x coordinate of the vertex (for that equation)?
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OpenStudy (anonymous):
I'm not sure..
jimthompson5910 (jim_thompson5910):
use a calculator if you need to (wolfram alpha is a good calculator to evaluate expressions like that)
OpenStudy (anonymous):
am i just evaluating it ?
OpenStudy (anonymous):
it said the result was 1..
jimthompson5910 (jim_thompson5910):
yes
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jimthompson5910 (jim_thompson5910):
it's not 1
OpenStudy (anonymous):
thats what wolfram said
OpenStudy (anonymous):
this is really confusing
jimthompson5910 (jim_thompson5910):
can you show me?
jimthompson5910 (jim_thompson5910):
take a screenshot and post what you got
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OpenStudy (anonymous):
i can't screen shot on my computer
OpenStudy (anonymous):
it won't let me put it as a fraction.. thats the problem
jimthompson5910 (jim_thompson5910):
you hit the printscreen key
jimthompson5910 (jim_thompson5910):
are you typing in 35/32 to represent \(\Large \frac{35}{32}\) ?
OpenStudy (anonymous):
yes, it won't let me put it as a fraction :/
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jimthompson5910 (jim_thompson5910):
what are you typing in exactly into wolfram alpha? Paste it here
OpenStudy (anonymous):
H(35/32)
jimthompson5910 (jim_thompson5910):
that's all?
jimthompson5910 (jim_thompson5910):
you were supposed to type in the right side, not the left
OpenStudy (anonymous):
there was only one box to type it, can you send me the link to wolfram?
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jimthompson5910 (jim_thompson5910):
you type in
-16(35/32)^2 + 35(35/32)
OpenStudy (anonymous):
it says: exact result 1225/24
OpenStudy (anonymous):
i think i got the answer
OpenStudy (anonymous):
19.1?
jimthompson5910 (jim_thompson5910):
are you sure? are you sure it's over 24?
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OpenStudy (anonymous):
i mean 64
OpenStudy (anonymous):
sorry
jimthompson5910 (jim_thompson5910):
that's fine
jimthompson5910 (jim_thompson5910):
so yeah, 1225/64 = 19.140625
OpenStudy (anonymous):
yes.. now im wondering if i send another question if you could verify my answer? i just need a second opinion
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jimthompson5910 (jim_thompson5910):
ok go ahead
OpenStudy (anonymous):
If 6c = 4T2 - 50, which of the following could T possibly be?
T = square root of negative 6 times C plus 50 over 4
T = square root of negative 6 times C minus 50 over 4
T = square root of 6 times C minus 50 over 4
T = square root of 6 times C plus 50 over 4
OpenStudy (anonymous):
I chose the last one
jimthompson5910 (jim_thompson5910):
does the last one say
\[\Large T = \sqrt{ \frac{6c+50}{4} } \]
??
OpenStudy (anonymous):
yes
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jimthompson5910 (jim_thompson5910):
it's correct
OpenStudy (anonymous):
okay ... Sarah wants to hang a painting in a gallery. The painting and frame must have an area of 75 square feet. The painting is 8 feet wide by 9 feet long. Which quadratic equation can be used to determine the thickness of the frame, x?
x2 + 17x - 3 = 0
x2 + 17x + 75 = 0
4x2 + 34x + 75 = 0
4x2 + 34x - 3 = 0
I chose the third one
OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
that's incorrect
jimthompson5910 (jim_thompson5910):
what equation do you start off with?
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OpenStudy (anonymous):
first i multiplied 9 times 8
OpenStudy (anonymous):
wait.. i think its the first one
OpenStudy (anonymous):
am i right?
jimthompson5910 (jim_thompson5910):
hint: find the area of this rectangle
|dw:1401233985765:dw|
jimthompson5910 (jim_thompson5910):
it might help to break it up like so
|dw:1401234014986:dw|