he amount of heat needed to raise 2.0 kg of a substance by 80 K is 33 kJ. What is the specific heat of the substance?
(Points : 3)
210

2,100

1,300

1.3 × 106

Question

he amount of heat needed to raise 2.0 kg of a substance by 80 K is 33 kJ. What is the specific heat of the substance?
(Points : 3)
       210 

       2,100 

       1,300 

       1.3 × 106

anonymous · Answer

Is chemestry?

anonymous · Answer

physics

johnweldon1993 · Answer

$$\large Q = cm\Delta T$$

Q = heat added
c = specific heat
m = mass
$\large \Delta T$ = change in temp

rearrange and solve for C

anonymous · Answer

I dont even know where to start with this problem. I got that part right 2.0*80*33=c

anonymous · Answer

i believe its d but im confused at the same time

anonymous · Answer

no its like 33/2*80 somethinglike that right

anonymous · Answer

am i right?

johnweldon1993 · Answer

$$\large C = \frac{Q}{m\Delta T}$$
$$\large C = \frac{33000J}{2.0kg \times 80K}$$

anonymous · Answer

i got 206.25 for that and it wasnt one of the answer choices, I'm trying to figure out what am i missing. i know you got the 33000 by multiplying 33*1000 because thats what k stands for

anonymous · Answer

@johnweldon1993

anonymous · Answer

@Hero

anonymous · Answer

i dont know what to do next

anonymous · Answer

please help

johnweldon1993 · Answer

Well hang on a second...lets look at units lol

$$\large C = \frac{Q}{m\Delta T}$$
$$\large C = \frac{33000 J}{2000g \times 80K}$$

We know  = C = J / gk so that looks right...now

$$\large C = \frac{33000}{160000gK }$$
C = .20625

well that doesnt help either O.o hmm