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Chemistry 7 Online
OpenStudy (anonymous):

what is the equilibrium constant for 4K + O2 <-> 2K2O

OpenStudy (anonymous):

keq = product/reactant

OpenStudy (anonymous):

Keq=[k2o]^2/[k]^4 * [o2]

OpenStudy (anonymous):

k=[cons.of products]/cons.of reactants]

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