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Mathematics 12 Online
OpenStudy (anonymous):

discuss the convergence of

OpenStudy (anonymous):

\[\sum_{n=0}^{\infty} \frac{ (n^2+3) }{ (3n+4)(4n^3-1) }\]

OpenStudy (anonymous):

the limit= 1/12 its possible to find it :) so its converge... if u wanna to know without finding the limit try test

OpenStudy (anonymous):

how did you solve

OpenStudy (anonymous):

simply :- Coefficient of the largest power in the numerator /Coefficient of the largest power in the denominator

OpenStudy (anonymous):

oh so you solved the denominator first

OpenStudy (anonymous):

i dint solve lol its just ovs n^2/12 n^4 take the coeffecient 1/12 as the limit :)

OpenStudy (anonymous):

oh i see

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