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discuss the convergence of
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\[\sum_{n=0}^{\infty} \frac{ (n^2+3) }{ (3n+4)(4n^3-1) }\]
the limit= 1/12 its possible to find it :) so its converge... if u wanna to know without finding the limit try test
how did you solve
simply :- Coefficient of the largest power in the numerator /Coefficient of the largest power in the denominator
oh so you solved the denominator first
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i dint solve lol its just ovs n^2/12 n^4 take the coeffecient 1/12 as the limit :)
oh i see
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