Explain the difference between a combination and a permutation.
\[k!~\binom{n}{k}=(n)_k\]
Sure! Lets say you are choosing different combinations for a computer password. Then if you (for the sake of the understanding, lets say) got 12345 and you choose 5 4 different numbers, then saying 1,2,3,4 is not the same as saying 1,2,4,3 this is permutations. Now, combinations. You have 15 players, and choosing 5 for a team. If you say name1, name2, name3, name4, name5 that would be the same as saying name1, name4, name2, name3, name5 because the same ppl are playing.
one is a multiple of the other
a permutation depends on order, it counts the number of shuffles a set of elements can take a combination does not consider order and simply counts the number of groupings that a set of elements can take {a,b,c} has 6 permuations: abc acb bac bca cab cba but it only has one combination: abc: in any order.
simply: permutation is generally done when you need to find the number of ways a "set of things can be arranged " and combination is when you need to find the no of ways "a set of things can be selected".
nPr is r! times greater than nCr
if you try to calculate each in terms of n and r \(\LARGE\color{black}{ \bf nCr=\frac{n!}{r!(n-r)!}}\) \(\LARGE\color{black}{ \bf nPr=\frac{n!}{(n-r)!}}\)
\[k!~nCk=nPk\] \[nCk=\frac{nPk}{k!}\]
yeah ... had trouble reading that sentence lol
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