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Mathematics 21 Online
OpenStudy (anonymous):

Explain the difference between a combination and a permutation.

OpenStudy (amistre64):

\[k!~\binom{n}{k}=(n)_k\]

OpenStudy (solomonzelman):

Sure! Lets say you are choosing different combinations for a computer password. Then if you (for the sake of the understanding, lets say) got 12345 and you choose 5 4 different numbers, then saying 1,2,3,4 is not the same as saying 1,2,4,3 this is permutations. Now, combinations. You have 15 players, and choosing 5 for a team. If you say name1, name2, name3, name4, name5 that would be the same as saying name1, name4, name2, name3, name5 because the same ppl are playing.

OpenStudy (amistre64):

one is a multiple of the other

OpenStudy (amistre64):

a permutation depends on order, it counts the number of shuffles a set of elements can take a combination does not consider order and simply counts the number of groupings that a set of elements can take {a,b,c} has 6 permuations: abc acb bac bca cab cba but it only has one combination: abc: in any order.

random231 (random231):

simply: permutation is generally done when you need to find the number of ways a "set of things can be arranged " and combination is when you need to find the no of ways "a set of things can be selected".

OpenStudy (solomonzelman):

nPr is r! times greater than nCr

OpenStudy (solomonzelman):

if you try to calculate each in terms of n and r \(\LARGE\color{black}{ \bf nCr=\frac{n!}{r!(n-r)!}}\) \(\LARGE\color{black}{ \bf nPr=\frac{n!}{(n-r)!}}\)

OpenStudy (amistre64):

\[k!~nCk=nPk\] \[nCk=\frac{nPk}{k!}\]

OpenStudy (amistre64):

yeah ... had trouble reading that sentence lol

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