For a certain procedure, a cat is anesthetized (drugs are eliminated exponentially from the blood stream). Of any drug in the blood stream, the body will eliminate half in 3 hours. If it takes 30 milligrams of the drug to anesthetize the cat, what single dose is needed for a 1 hour operation?
@amistre64
If in 3 hours, half the drug is eliminated, then the whole thing will be completed in 6 hours. If 30 ml of drug is required to anesthetize the cat in 6hrs, so complete the process in 1 hr, the dosage should be equivalent. So, i think it should be 6*30=180 ml.
finally got back on. it turned out to not be 180 :/
That's because Sourav was thinking linearly when the drug really decreases in concentration exponentially. Since we know it's exponentially decaying, what do you think the function will look like?
not sure actually
\[Q(t)=Q_0 e^{-at}\] This is what exponential decay looks like. Q(t) represents the concentration Q as a function of time t. Qo is the initial amount, and you can prove that to yourself by plugging in t=0 to this formula. The negative sign shows that it is indeed decaying exponentially. They say that for any amount you put in, you'll have exactly half left after 3 hours. So we can just plug that in: \[\frac{Q_0}{2}=Q_0e^{-a3}\] and use this to solve for our rate constant, a. Then next we need to make sure that by the end of the operation that we have 30 mg of concentration. So that means our final amount has to be 30 since the cat's blood metabolizes it over time and we need to put in more. So to calculate the amount we need to put in initially, we plug that final concentration in along with the time it takes to get there. Q(1)=30 is what that is in symbols since after 1 hour we should have 30 mg left since the procedure is over we don't want it to be higher than that.
oh so it comes out to be 30?
Yeah, you would want to inject more than 30 mg at the beginning of the procedure, otherwise the cat will wake up! You have to have at least 30 mg in the cat's bloodstream during the course of the entire operation.
that's what the answer is though. i just saw that it was in the question
isn't* sorry
Read what I wrote, think about it, and try to understand what's going on. I'll be back in about an hour.
Back
Yeah it wasn't 30 :/
30 is the final concentration. But your answer isn't the final concentration. You are solving for the initial concentration.
oh shoot. how do you proceed. sorry i didn't notice. -.-
I've written out the whole procedure in that longer post above. If you have trouble understanding it just ask and I'll help you understand.
Ok. i need help please
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