Question

Using the following equation, find the center and radius of the circle. x2 + 4x + y2 − 6y = −4

Answer 1

@Jennjuniper can you help?

Answer 2

@mipie13 can you help?

Answer 3

@cwrw238 can you help?

Answer 4

The attached plot may give you some ideas.

Answer 5

i will take a look at it!

Answer 6

i need to know how to find the answer with the equation

Answer 7

Organise the x and y terms so that they are aligned together so that it is easier to understand. Also subtract 3 from both sides:

x^2 - 4x + y^2 + 6y = -3

Complete the square for each set of terms:

x^2 - 4x + 4 + y^2 + 6y + 9 = 10

Factor:

(x - 2)^2 + (y + 3)^2 = 10

The centre of a circle is at (0,0) and the radius is the square root of the result, thus:

Centre = (2, -3)
Radius = √10

Answer 8

Centre = (2, -3)
Radius = √10

Answer 9

1. (x^2+4x+4)-4+(y^2-6y+9)-9=-4
(x+2)^2+(y-3)^2=9
(x+2)^2+(y-3)^2=3^2
Circles follow the form: (x-a)+(y-b)=r^2
Therefore the center of the circle is at (-2,3) and the radius is 3.

Answer 10

thank you both :D i see what i wasnt understanding at first but using your responces i can figure out these problems now

Answer 11

try google and type your question in that's what I normally do