Find (3y-1)^2 please help because i am not that good at math and i dont have much time to complete this
please show your work if possible thank you and God bless!
You can either use \(\large \color{blue}{ \bf (a-b)^2=a^2-2ab+b^2 }\) or pascal's Triangle \(\Large\color{red}{ \bf 1 }\) \(\Large\color{red}{ \bf 1~~~~~~~~1 }\) \(\Large\color{blue}{ \bf 1~~~~~~~2~~~~~~~1 }\) \(\Large\color{red}{ \bf 1~~~~~~3~~~~~~~~3~~~~~~~1 }\) \(\Large\color{red}{ \bf 1~~~~~~4~~~~~~~6~~~~~~~4~~~~~~~1 }\) \(\Large\color{red}{ \bf 1~~~~~5~~~~~10~~~~~~10~~~~~~5~~~~~~1 }\)
i havent learned pascals triangle yet, so i am guessing it would be 3^2-2(3)(1)+1^2 is that correct?
well (3y)^2-2(3y)1+1^2 don't forger the "y". Now , expand it...
hello?
It would be: \( (3y)^2 - 2(3y)(1) + (1)^2\)
so thats the final answer or is it possible to simplify it
Simplify it. \((3y)^2 - 2(3y)(1) + (1)^2 = 9y^2 - 6y + 1\)
oh ok thank you
You are welcome.
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