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3rd derivative of y=a/2(e^(x/a)+e^(-x/a)) (steps please)
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Do you know what hyperbolic cosine and sine are?
i have the 2nd derivative worked out already y'' = a/(2a^2 ) ( e〗^(x/a) + e^(-x/a) )
needs to be worked out through differentiation
If you can get the second derivative, what's stopping you from getting the third?
need to investigate (d^(n)y)/(dx^(n)) for all positive odd integers for n
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Well, a useful identity to know is \[\cosh(t)=\frac{e^{t}+e^{-t}}{2}\]\[\sinh(t)=\frac{e^{t}-e^{-t}}{2}\] it's pretty straightforward to see that they are each their own derivatives, and what you have is essentially just the chain rule. For example, \[\frac{d^n}{dx^n}(Ae^{b\ x})=Ab^n e^{b\ x} \] should make some sense.
thanks
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