Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is 'a' and the phase of A is ahead by (pi/3) than that of B and the distance AP is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter

Question

anonymous · Answer

resultant amplitude will be vector sum at point P.Which is 
root( a^2 + a^2 + 2a.a.cos (phase difference)) 
phase difference will be pi/3 - pi = -2pi/3 ... subtracting because B is closer to P than A
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