Question

ALGEBRA 1 HELP: (Pictures Included)

Find the x- and y-intercepts of the graph of each equation. (#9, and 13)

Draw a line with the given intercepts. (#15)

Tell whether the graph is a vertical line or a horizontal line. (#23)

Write the equation in standard form using integers. (#31, and 33)

Answer 1

(pg. 331, #9, 11, 13, 15, 19, 23.)

Answer 2

(pg. 345, #6, 7, 8, 15, 16.)

Answer 3

what do you need help with first

Answer 4

hello?

Answer 5

I need help with the very first ones I posted. Lets just start on #9, 13.

Answer 6

@dan815 Are you still there?

Answer 7

finding the y-intercept, you plug in 0 for x and solve

Answer 8

for the x-intercept, you try to factor and solve for both x values

Answer 9

Could you like show me an example? Sorry I'm just really bad a this stuff.

Answer 10

OK, we will use one of your problems

Answer 11

y intercept
x - 2y = 2
0 - 2y = 2
Divide both sides by 2
y = 1
(0, 1)

x intercept
x - 2(0) = 2
x - 0 = 2
x = 2
(2, 0)

Answer 12

does that make sense to you?

Answer 13

@jtryon it does make sense.

Answer 14

So what would I do from there?

Answer 15

@marissalovescats could you possibly help me with these final questions, if it's not a bother? :) Please and thank you.

Answer 16

Which ones?

Answer 17

Well I already got help with #9 on the first set, 13 is too complicated for me to do on my own, so probably just for now, the first set listed at the very top.

Answer 18

So 13?

Answer 19

Yeah 13

Answer 20

Heres a couple definitions for you:

1. Parallel lines have the same slope and different y intercepts
2. Perpendicular lines have reciprocal slopes and different y intercepts.
3. Neither has well... slopes that aren't either of these to each other.

Which one do you thing 13 is?

Answer 21

Let me know if you don't know what reciprocal slopes are.

Answer 22

Could you please respond to me? Do you not need help anymore or what

Answer 23

I'm not sure which one is 13, and I did but I forgot. Sorry I do still need help, my internet it just messing up

Answer 24

Okay, that's fine. Well if you scroll up and click on the pictures you posted you could see what number 13 is. It's asking if the two equations given are parallel, perpendicular, or neither.

Answer 25

I'm guessing one with perpendicular lines and reciprocal slopes.

Answer 26

What do you mean?

Answer 27

I'm honestly not sure at all.

Answer 28

Okay... you asked me to help you with 13 right?

Answer 29

Yes

Answer 30

Okay and I explained to you what makes lines parallel perpendicular or neither, so what would 13 be?

And I asked if you needed an explanation on what a reciprocal slope is

Answer 31

Yes I do need a explanation.

Answer 32

I forgot to mention perpendicular lines have negative reciprocal slopes. So, how to do that is doing -1/slope so if we have 2 as a slope our negative reciprocal would be -1/2

If we had 3/4 as a slope, the negative reciprocal would be -4/3.

Make sense?

Answer 33

So, is number 13 parallel, perpendicular, or neither?

Answer 34

I believe it is perpendicular.

Answer 35

Great job! Any others?

Answer 36

No I meant the ones above that! Lol, I was wondering where you got that parallel, perpendicular, or neither stuff from.

Answer 37

Are you still there? I really need help with these? If you need clarification on which ones I need, we go by one set at a time, if it's easier.

Answer 38

The very first link you provided: To find x intercept, put y = 0 in the equation and solve for x. To find y intercept, put x = 0 in the equation and solve for y.
For example, #9) x - 2y = 2
For x intercept, set y = 0 and solve for x: x - 0 = 2. x = 2 is the x-intercept.
For y intercept, set x = 0 and solve for y: 0 - 2y = 2. y = -1 is the y-intercept.

Answer 39

I got that already, but 13 is where I'm stuck

Answer 40

The person who answered #9 before made a mistake in the sign for the y-intercept.

Answer 41

oh okay. Thanks for correcting that.

Answer 42

#13) -5x + 3y = -7.5

For x intercept, set y = 0 and solve for x: -5x + 0 = -7.5. x = -7.5/(-5) = 1.5 is the x-intercept. The point is (1.5, 0)
For y intercept, set x = 0 and solve for y: 0 + 3y = -7.5. y = -7.5/3 = -2.5 is the y-intercept. The point is (0, -2.5)

Answer 43

For #15, on the graph paper mark the point -1 on the x-axis. The point should be to the LEFT of the origin. This point will represent the x-intercept of -1.
On the negative y-axis mark the point -4. The point should be BELOW the origin. This point will represent the y-intercept of -4.
Draw a straight line passing through the above two points and that will be the graph of the line.

Answer 44

Could you possibly draw an example of 15 for me? Please?

Answer 45

Sorry I had to run to the store for my uncle. But it looks like @ranga's got it :)

Answer 46

y = constant will be a horizontal line.
x = constant will be a vertical line.
Use this info to answer #23.

Answer 47

Standard form of a straight line is: Ax + By = C
#31) y = 2x + 5
subtract y from both sides: 0 = 2x - y + 5
subtract 5 from both sides: -5 = 2x - y.
Thus, the standard form of the equation is: 2x - y = -5

Put #33 also in the form Ax + By = C.

I have to go now.

Answer 48

Thank you for your help! :)

Answer 49

@marissalovescats So I need your help once again, haha. Since you already helped me with 13 on the second set, and your explanation helped me do #15 on my own, I just need help with (#9, 11, 19, 23.) Please and thank you.

Answer 50

Actually just 19 and 23.

Answer 51

Okay I can do that lol

Answer 52

Actually we can skip those too, haha. I just need help with the final set of problems the image is up there with them. (#6, 7, 8, 15, 16.)

Answer 53

Okay so for 19, they give you an equation and the slop of that equation is -3

It also says the new line you're going to create is perpendicular to the one given.

So this new line will have a slope that is a negative reciprocal of -3. Which would be what?

Answer 54

Oh.. okay

Answer 55

Okay for 6, the first thing you want to know is the basic absolute value graph:

y=abs(x) looks like this:

Answer 56

okay makes sense, am I going to have to draw that?

Answer 57

To shift this graph left or right, you have a number inside the absolute value bars along with the x. (But remember it's like finding a vertex) If it's y=abs(x-2) then the graph will actually be on +2 like this:

Answer 58

If you want to move the graph up or down, the number is outside the absolute value bars and is true to it's meaning. So if we had y=abs(x)+1 we would have:

Make sense?

Answer 59

So, in number 6, how would that graph be related to y=abs(x)?

Answer 60

I think it would be related to y=abs(x) by the second one, sorry I'm kind of confused still.

Answer 61

I'm sorry if I'm being difficult, but I'm just really terrible at this sort of stuff.

Answer 62

Yes you are right. It's related to it because it's the same graph, just shifted up 3 units. The equation of that graph is y=abs(x)+3