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Mathematics 15 Online
OpenStudy (anonymous):

Please Help Me With This...I will medal PicnicTech markets 3 versions of its Picnic Egg Boxes: the Golden Deluxe, containing 3 gold eggs and 1 plain egg; the Regular, containing 2 gold and 2 plain; and the EconoLunch, containing just 1 gold egg and 3 plain ones. The corner store has 3 Golden Deluxes on sale, 2 Regulars, and 5 EconoLunches. This is all shown in the tree diagram below.You buy a Picnic Egg Box at random and select an egg from it at random. The egg is gold! Use a probability tree diagram to calculate the probability that the box you bought was a Regular.

OpenStudy (anonymous):

OK, first step is you want to draw lines to represent the first set of options Second step: Convert the percentages to decimals and put those on the appropriate branch in the tree Third step: Draw the next set of branches Fourth step: Draw any other branches that you are given from the question

OpenStudy (anonymous):

OpenStudy (anonymous):

This helps me none.

OpenStudy (anonymous):

In what follows, "g" stands for "gold", and "p" for plain. Your experiment has a total of 3 + 2 + 5 = 10 outcomes. An outcome yields one of the following egg scenarios: gggp with probability 3/10 ggpp with probability 2/10 gppp with probability 5/10 For each scenario we now consider the experiment of drawing an egg at random. The respective probabilities of drawing a plain one are 1/4 (for gggp), 2/4 (for ggpp), and 3/4 (for gppp). Thus, the probability of drawing a plain egg in the entire experiment is: (3/10)*(1/4) + (2/10)*(2/4) + (5/10)*(3/4)

OpenStudy (anonymous):

Maybe that will help with the understanding...

OpenStudy (anonymous):

Okay....you are the second person who has like gone on Yahoo and copied and pasted.

OpenStudy (anonymous):

It's wrong. Thanks a lot.

OpenStudy (anonymous):

P(gold box and gold egg) = 3/4 * 1/2 P(econolunch and gold egg) = 3/10 * 1/4 P(regular box and gold egg) = 2/10 * 2/4 Easier way: Count all the eggs, there is 40 in total in 10 boxes. Then count how many of them are golden. There is 15 golden eggs in 5 gold boxes, 3 golden eggs in 3 econolunches, and 4 golden eggs in 2 regular lunches so that's a total of 22 golden eggs out of a total of 40. Then the probability is: P(Choosing a Gold egg)=n(A)n(S)=2240=1120=55%

OpenStudy (anonymous):

That should be the correct answer @moemand

OpenStudy (anonymous):

You're kidding right? .55....55% Same thing as 11/20. =WRONG.

OpenStudy (anonymous):

It should be... 55%

OpenStudy (anonymous):

It is Regular*** Not golden. Look at the question. 55% is not even an answer choice

OpenStudy (anonymous):

What are your choices?

OpenStudy (anonymous):

OpenStudy (anonymous):

How about 1/2?

OpenStudy (anonymous):

I will explain if that is correct.

OpenStudy (anonymous):

Well I won't be able to tell until the end.

OpenStudy (anonymous):

No you were still wrong.

OpenStudy (anonymous):

Guessing games isn't helping at all. If you don't know don't answer.

OpenStudy (anonymous):

I am going to step out on this one

OpenStudy (kropot72):

|dw:1401347861944:dw| P(gold) = (0.3 * 0.75) + (0.2 * 0.5) + (0.5 * 0.25) = 0.45 Given that the egg is gold, the probability that it came from a regular box is \[\frac{0.1}{0.45}=0.222\]

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