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Integration:
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\[\LARGE \int x~(2x+5)^8~dx\]
We can use integration using substitution for this one.
assume 2x+5=u
Right
Then, du/dx=2 So, du=2dx
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\[\int\limits_{}^{}x(2x+5)^8dx=\int\limits_{}^{}xu^8*1/2*du\]
Now, from the substituion u=2x+5, we get x=(u-5)/2
\[\int\limits_{}^{}(\frac{ 1 }{ 2 })(\frac{ u-5 }{ 2 })u^8du=\int\limits_{}^{}\frac{ u^9-5u^8 }{ 4 }du\]
Can you take it from here? @Luigi0210
Yes, I got the rest, thanks for the explanation as well :)
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Yep! Just make sure to leave your answer in terms of x, not u
Math @-@
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