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Mathematics 9 Online
OpenStudy (anonymous):

I don't know where i am going wrong

OpenStudy (anonymous):

For what values of k the expression kx^2 + (k+1)x +2 will be a perfect square of a linear polynomial?

OpenStudy (anonymous):

I would type what i did

OpenStudy (kainui):

I simply just completed the square and then took the stuff that was leftover and set it equal to zero.

OpenStudy (kainui):

Uhh I think that works. Does that make sense? I'm sorta out of it.

OpenStudy (anonymous):

Let the linear polynomial be ax+b So, kx^2 + (k+1)x +2 = (ax+b)^2 kx^2 + (k+1)x +2 = a^2 x^2 + 2ab x + b^2 Comparing the terms k = a^2 (k+1) = 2ab b^2 =2

OpenStudy (anonymous):

Well , @Kainui i think so I will just check that out

OpenStudy (anonymous):

Do u mean adding [(k+1)/2]^2 to both sides

OpenStudy (anonymous):

We can write k -2ab -1 =0 b is sqrt 2 |dw:1401362876847:dw|

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