Question

PLEASE HELP! I am SO stuck. Ellipse question with attachment below.

Answer 1

@whpalmer4

Answer 2

@amistre64

Answer 3

@Hero

Answer 4

I would love to help! But I do not see any attachment of an ellipse.

Answer 5

@IMStuck

Answer 6

@IMStuck I attached the file, that was my mistake... Can you please help me solve a few problems? I'll post more after this one and give you best answer if you help me.

Answer 7

the center is the same for pretty much any setup .... look at the x y parts and see how they are adjusted

Answer 8

I seriously don't know how to go about any part of the problem.

Answer 9

given some center point (a,b)

the center of an equation will tend to be written in as: (x-a) and (y-b)

Answer 10

I'm sorry, I just don't understand.

Answer 11

The center for an ellipse is found just like you would find the center of a circle. The forula is (x-h)^2 + (y-k)^2, where h and k are the centers. So you are given (x + 3)^2; filling in the +3 to the formula (x-h)^2, you get (x-(-3)) [x minus a negative gives a positive, right, which is what your equation is telling you? The center is (x + 3)^2.] The x coordinate of the center is -3. Do the same with y. (y - 2)^2 is a y coordinate of +2. The easy way to do this is to remember that the centers have the OPPOSITE signs of what is inside the parenthesis. (X + 3)^2 has an x coordinate of -3 and (y - 2)^2 has a y coordinate of +2. So the center is located at (-3, 2). That's done. Oh, that's all you need! Gotcha! The rule of the opposite sign thing applies to all circles and ellipses! Anything else, just ask!

Answer 12

x + 3 = 0, solve for x

y - 2 = 0, solve for y

that gets you your center ....