Question

PLEASE HELP!
Find all solutions in interval (0,2pi)

2 sin^2 (x) + cos (x) = 1

Write in terms of pi


PLEASE HELP!

Answer 1

PLEASE HELP!!

Answer 2

\[\Large\rm \sin^2x=1-\cos^2x\]We can rewrite this as a quadratic involving cosx

Answer 3

use the identities

Answer 4

\[\Large\rm 2(1-\cos^2x)+\cos x=1\]

Answer 5

Understand that step? :o

Answer 6

I would but I don't know what subject this is for

Answer 7

would the answer be 2pi and 2pi/3.


Please someone check it!

Answer 8

I think so

Answer 9

please someone check it over, this is so important for me

Answer 10

k sec,

Answer 11

so sorry but I can't

Answer 12

thank you zepdrix!!!

Answer 13

I'm coming up with factors of:\[\Large\rm (\cos x-1)\left(\cos x+\frac{1}{2}\right)=0\]

cos x=1 gives us the 2pi, that looks good!
cos x = -1/2 should give us a little bit more than just 2pi/3,
you're on the right track though.

Answer 14

so its not 2pi/3 ? :(