The figure below shows trapezoid ABCD on a coordinate plane. Which of the following expressions represents the area of this figure in square units? a.148 b.74 c.37 d.18 https://media.glynlyon.com/g_geo_ccss_2013/9/img_geo_9_5a_graphing_6.gif
@elementwielder
im sorry but i dont really have time right now to answer questions as i am studying for my final exams tomorrow
I's no problem, good luck!
It's
thank you and to you as well @Whitemonsterbunny17 please help
@Embryo
The area of a trapezoid is given by\[Area=\frac{ a+b }{ 2 }h\]where a and b are parallel lines segments, and "h" is the height from "a" to "b", now because you have a graph, you have points, so you need to calculate the distances between the different points, i'll tell you this, "a" in that formula is the distance from point B to C, "b" is the distance from point A to D, and the height "h" is the distance from point B to E. After you find all those you plug them into the Area formula
I got from A to D is 333 units. From D to C is 74 units. From C to B is 37 units. From B to A is 74 units. @Embryo
Alrighty, so from the numbers you got (i didn't calculate it, i trust you), the way the variables in the Area of a trapezoid equation as i stated should be given these values, a=37, b=333, and then h=not what you got h should be the distance from point B to point E, not B to A
unless you just typed A and meant E, not sure
For B to E I got 37
alrighty, so carrying on from the previous stuff, a=37,b=333, and h =37, plugging those into the area formula we get\[Area=\frac{ 37+333 }{ 2 }37\]which is an incredibly large number, are you surrrreeeee, i'll go ahead and calculate this as well, because these are some big numbers
i think you took the distances wrong, because if you think about it, you can't have 37 units in between any of those points
you must have forgotten to take the square root
yup, okay, so you forgot to take the square root of all the distances, after you take the square roots, you should get the answer\[Area=\frac{ \sqrt{37}+\sqrt{333} }{ 2 }\sqrt{37}=74\]that's good, you took the distances correctly, but forgot to take the square root, just remember that part and you'll be fine
Okay thank you. I have one more that I don't understand. It's the same figure and it wants the area of EBCD.
go ahead and ask it, i'll help if i can
oh wait lol, it's the same figure okay XD
lol ya
Alrighty, well one way to approach this problem now, is to check one thing, if Line AB is equal in length to Line CD, if they are, then you can calculate the area of the square that i will attach, labeled CBEX, and add the area of the triangle BAE
I have to go do something but I will be done in about 25 minutes. Will you still be available?
I will, see you when you return
Hi I'm sorry it took longer than i thought last night and when I was done it was really late @Embryo
Ah it's totally fine
Could you help me with that problem now?
Of course, ask away
The one you started to help me with last night
ahh oh yeah sorry, forgot lol, one sec to refresh myself on the question
Alrighty, well one way to approach this problem now, is to check one thing, if Line AB is equal in length to Line CD, if they are, then you can calculate the area of the square that i will attach, labeled CBEX, and add the area of the triangle BAE
What did you say the measurement for BE was?
Was is sqrt 37?
yup
So what would my equation look like?
The equation for the area of the square? is that what you mean?
ya
Excuse me, i shouldn't say that it's a square, we don't exactly know if all sides are equal, so we need to calculate the length of at least 2 sides to know the area of that "rectangle," we can do that by finding the length of BE as we found to be sqrt{37} and multiplying it by the length of BC which you found to be sqrt{37}, so hey, would you look at that, it does happen to be a square, so the area is easy to find then
ok give me a sec
I got 37 @Embryo
SO when you divide it the final answer is 37 right?
Yes, 37, that should be the area of that square (now that we know it is indeed a square), but we're not done yet, you need to find the area of that triangle CXD that i made the picture for, but since we don't actually know where point X is, we have to do something a little different
like i said earlier, you need to find the length of CD and BA, and figure out if they are equal (which they should be), go ahead and see if they are
I am sorry if this seems like a lot to do for one problem, but everything i'm telling you is necessary to get the right answer
So the servers crashed and idk when you'll be back to finish this problem, but fear not, i will be here to answer your question till the end, but if i don't respond fast, it's probably because i'm eating dinner
Okay I'm so tired of this problem. Can you please quickly help me finish this @Embryo
The thought process for calculating the area of BCDE is like this, you an obviously make a square from the trapezoid and calculate the area of that, but the problem is that we don't know what point X is at in the drawing i gave you (i'll attach it again), so we need to figure out if BA = CD, it that is true, then we know that the area of triangle BAE=CDX then we can just add up the area of the square BCDE and the triangle BAE which would give you the area of BCXE
yes please finish it because i got so many notifications
Since we found out earlier that BCXE is indeed a square, we can calculate the area of the square to be the length of BC^2
And yes, i would love to finish it as well
thanks
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