Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

A company launched four new products. The market price, in dollars, of the four products after different number of years is shown below: The price of which product will eventually exceed all others?

OpenStudy (anonymous):

OpenStudy (anonymous):

@ranga

OpenStudy (perl):

im not sure, some of those functions are not linear

OpenStudy (ranga):

Are you allowed to use any calculator with regression functions?

OpenStudy (anonymous):

yes

OpenStudy (ranga):

For product 1, the equation is easy to find. y = 2^x. We can ignore product 4 because the price goes up and down or remains the same. We need to find a non-linear regression line for products 2 and 3 and compare it to product 1 to see which one will rise the fastest.

OpenStudy (ranga):

But without using any calculators, my guess is it is product-1. If you take the difference in price of each product from one year to the next, product-1 rises the fastest.

OpenStudy (anonymous):

but arent we looking for exponential?

OpenStudy (ranga):

Yes. But without using a calculator to find the exponential equation I am guessing how fast each one is rising by taking the difference, especially between year 4 and year 3: 4th - 3rd year prices Product1 8 Product2 2.40 Product3 7.20 Product4 -0.40 Product-1 seems to be climbing faster. If you want you can find the exponential fit for product3 and compare it to 2^x for product1 and see which one will be larger eventually.

OpenStudy (anonymous):

oh okay, thank you. do you mind assisting me with another problem?

OpenStudy (ranga):

I have to log off in less than two minutes though.

OpenStudy (anonymous):

oh okay thanks for your time

OpenStudy (ranga):

You are welcome.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!