You dissolve 1.50 grams of NaCI in 3.0 L of water. What is the molarity of the solution?

Question

abhisar · Answer

Hello @freyabeauchamp !

abhisar · Answer

Molarity = No. of solute moles/Volume of the solution

abhisar · Answer

Here NaCl is the solute, so lets calculate its amount first

abhisar · Answer

Molar mass of Na = 23 & Molar mass of Cl = 35, Now molar mass of NaCl will be 23 + 35 = 58

abhisar · Answer

Since 1.50 grams of NaCl is dissolved, we will have to calculate no. of moles in 1.50 grams.
No. of moles = Given mass/Molar mass

abhisar · Answer

= 1.50/58
=0.02 moles

abhisar · Answer

Now the final step, 
Molarity = 0.02/3
=$$8.62 X 10^{-3}$$

abhisar · Answer

Yes and dont forget to put the unit i.e moles/litre

anonymous · Answer

My internet stopped working earlier and i couldn't get back on! But thank you for your help and helping explain it!

abhisar · Answer

Anytime !