Question

Check my answer!

integral from 0 to infinity e^(-2t) sinht sin t/ t dt

I got
1/2 (π/4-cot^(-1)3 )

Answer 1

mind adding in parentheses so we can clarify your notation?

Answer 2

\(\Large \int \limits_0^\infty e^{-2t} \sinh t \dfrac{\sin t}{ t} dt = \dfrac{1}{2}(\dfrac{\pi }{4}-\cot^{-1}3)\)

Answer 3

need more clarification ?

Answer 4

no, looks good. one moment

Answer 5

used laplace transform

L[sin t/t] = cot^-1 (s)

Answer 6

ya that's what i got with that transform. gj

Answer 7

its exactly correct?