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Mathematics 15 Online
OpenStudy (anonymous):

I need help simplifying . !! FAN AND MEDAL.!

OpenStudy (anonymous):

\[\left( \sqrt{6+\sqrt{10}} \right)\left( \sqrt{2+\sqrt{3}} \right)\]

OpenStudy (anonymous):

Are you sure it's the square root of six plus the square root of ten, multiplied by the square root of two plus the square root of three?

OpenStudy (anonymous):

what are the any answer choices

OpenStudy (anonymous):

I'm sure and hold on I'll give you the options.

OpenStudy (anonymous):

Did you mean: \[\left( \sqrt{6}+\sqrt{10} \right)\left( \sqrt{2}+\sqrt{3} \right)\]

OpenStudy (anonymous):

\[A. 2\sqrt{3}+3\sqrt{2}+2\sqrt{5}+\sqrt{30}\]

OpenStudy (anonymous):

Yes that is what I meant.

OpenStudy (mathstudent55):

\(\left( \sqrt{6+\sqrt{10}} \right)\left( \sqrt{2+\sqrt{3}} \right)\) Put both radicands inside one single square root and multiply them out.

OpenStudy (anonymous):

\[B. (\sqrt{16})(\sqrt{5})\]

OpenStudy (anonymous):

C. \[\sqrt{12}+\sqrt{30}\]

OpenStudy (mathstudent55):

\(\left( \sqrt{6+\sqrt{10}} \right)\left( \sqrt{2+\sqrt{3}} \right)\) \( =\sqrt{\left( 6+\sqrt{10} \right)\left( 2+\sqrt{3} \right) } \)

OpenStudy (anonymous):

what is D?

OpenStudy (anonymous):

D. \[4\sqrt{3}+9\sqrt{2}+4\sqrt{5}+ \sqrt{30}\]

OpenStudy (anonymous):

But you did mean what I said right?

OpenStudy (mathstudent55):

\(=\sqrt{\left( 6+\sqrt{10} \right)\left( 2+\sqrt{3} \right) }\) \( = \sqrt{12 + 6 \sqrt{3}+ 2\sqrt{10} + \sqrt{30} }\)

OpenStudy (anonymous):

I THINK IT IS C

OpenStudy (mathstudent55):

\(\left( \sqrt{6}+\sqrt{10} \right)\left( \sqrt{2}+\sqrt{3} \right)\) \(=\sqrt{12} + \sqrt{18} + \sqrt{20} + \sqrt{30} \) \(= 2\sqrt 3 + 3 \sqrt 2 + 2 \sqrt 5 + \sqrt{30} \) This is choice A.

OpenStudy (anonymous):

@mathstudent55 You're correct. Thank you. :)

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