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Mathematics 9 Online
OpenStudy (anonymous):

Need help simplifying.!!! FAN AND MEDAL.!!

OpenStudy (anonymous):

\[(\sqrt{32})(\sqrt{2})\]

OpenStudy (anonymous):

@mathstudent55

OpenStudy (anonymous):

the squareroot of 32 simplifies to 4 root2 so you just multiply 4 root 2 by root 2. You understand

OpenStudy (anonymous):

Yes so it would be 8

OpenStudy (anonymous):

yep!

OpenStudy (anonymous):

Thanks.! :)

OpenStudy (imstuck):

As long as the indexes are the same, you can multiply them. The index here is 2, that is, they these are square roots. If they were both cube roots, you could multiply them, too. But they are both square roots, so \[\sqrt{32}\times \sqrt{2}=\sqrt{64}\]Since 64 is a perfect square, that simplifies to 8!

OpenStudy (anonymous):

Thank you too.!

OpenStudy (anonymous):

no problem! any other questions?

OpenStudy (anonymous):

\[\sqrt{x+2}=2\sqrt{3}\]

OpenStudy (anonymous):

Solve.

OpenStudy (anonymous):

ok so square both sides of the equation

OpenStudy (anonymous):

idk how to square x+2

OpenStudy (anonymous):

it would just be x+2=12 because when you square \[\sqrt{x+2}\] you would just get x+2 understand?

OpenStudy (anonymous):

But how would x+2 =12 Wouldn't it be 2x

OpenStudy (anonymous):

why do you think it would be 2x

OpenStudy (anonymous):

Because adding x to 2 would just be 2x because x is not a number

OpenStudy (anonymous):

ok well you are trying to solve for x so think of it like this root 4 times root 4 it equals 4 right so when you do \[\sqrt{x+2} \times \sqrt{x+2}\] it would equal x+2 right.

OpenStudy (anonymous):

so if x+2=12 then x=10 do you understand

OpenStudy (anonymous):

actually this is x+2=144 so x=142

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