According to Charles’ Law, if the volume of a sample of O2 gas is doubled while pressure is held constant, what happens to the absolute temperature?
a) It doubles.
b) It decreases by ½.
c) It remains constant.
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OpenStudy (anonymous):
I know Charles' law is V = kT or VR/TR = VS/TS.
OpenStudy (jfraser):
if you rearrange the first equation, you'll get this:\[\frac{V}{T} = k\] so if the V/T ratio must be constant, what must the answer be?
OpenStudy (abhisar):
Volume is directly proportional to temperature
OpenStudy (abhisar):
now guess the correct answer
OpenStudy (anonymous):
it remains constant or does it double?
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OpenStudy (jfraser):
V/T must always be constant for a given amount of gas. If V doubles, ....
OpenStudy (abhisar):
It is directly proportional. What do u understand by this ?
OpenStudy (abhisar):
This means the same change will occur to both
OpenStudy (abhisar):
Now can u guess the answer ?
OpenStudy (anonymous):
If volume doubles then temperature must also double?
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