Question

integral 1/cy-1 dy

Answer 1

\[\int\limits \frac{1}{cy-1}dy\]

Answer 2

with c being a constant

Answer 3

i would think the answer is: ln(cy-1) , but it's not

Answer 4

+C

Answer 5

still wrong

Answer 6

answer should be: 1/c . ln(cy-1)

Answer 7

for some reason..

Answer 8

\[\int\limits \frac1{cy-1}\,\mathrm dy\\=\frac1c\int\frac1{y-1/c}\,\mathrm dy\\
=\frac1c\log{(y-1/c)}+C\]

Answer 9

no, don't think that's right
checked wolframalpha

Answer 10

nevermind, figured it out

Answer 11

used substitution

Answer 12

\[\int\limits \frac1{cy-1}\,\mathrm dy\\=\frac1c\int\frac c{cy-1}\,\mathrm dy\\
=\frac1c\log{(cy-1)}+C\] its the same thing

Answer 13

what did you get ?

Answer 14

the same

Answer 15

used u= cy-1, etc..

Answer 16

got 1/c * ln(cy-1)

Answer 17

thanks