Question

MEDAL simplify x^2+2x-35/x^2+4x-21

Answer 1

@neer2890 are you abkle to help with this one?

Answer 2

you have to use factorization method for this one
for the equation ax^2+bx+c=0
we always factorize the acx^2 such that it becomes bx
for e.g.,
x^2+2x-35=0
x^2+7x-5x-35
=x(x+7)-5(x+7)
=(x+7)(x-5)

Answer 3

here when we multiply x^2 and -35 its -35x^2
also when we multiply 7x and -5x it becomes -35x^2

Answer 4

using same method for x^2+4x-21
this becomes (x+7)(x-3)
so when we divide both of them
(x+7) cancels out
and it remains
\[\frac{ (x-5) }{ (x-3) }\]

Answer 5

You have written x^2+2x-35/x^2+4x-21 = \(x^2 + 2x - \dfrac{35}{x^{2}} + 4x - 21\)

Is that what you meant? If not, you may wish to add some parentheses to make it say what you want.

Answer 6

alternatively you can use this formula for finding the roots of the quadratic equation
\[ax ^{2}+bx+c=0\]
\[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]