Question

Find all solutions in interval [0,2pi)

Sec theta + sq.root 2 = 0

Find solution (s) in terms of pi (radians)

Answer 1

Have you considered \(\sec(\theta) = 1/\cos(\theta)\)?

Answer 2

for answers i got 3pi/4 and 5pi/4 but im not sure thats right

Answer 3

How did you get that?

\(\cos(\theta) = -\dfrac{\sqrt{2}}{2}\)

Look sto me like you have it. Why do you doubt?

Answer 4

\[\theta =\sec ^{-1}\left(-\sqrt{2}\right)=\frac{3 \pi }{4} \]