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Another representation, in polar coordinates, of the point (2,pi/6) is (___,7pi/6).
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use the formulas r = sqroot(a^2+b^2) and tan (theta) = b/a . Plug in a = 2 and b = pi/6 Good luck! :)
|dw:1401480994278:dw|So we're facing this way, at an angle of pi/6
If we move outward a distance of 2, it puts us here,|dw:1401481044228:dw|
|dw:1401481062221:dw|If we add pi to our angle, we're over here, at 7pi/6. Facing this direction. Hmm how would we get to that same point? Should we move forward 2 units or no?
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