Question

please help me.

Answer 1

Did you give it any attempt?

Answer 2

I don't understand it at all.

Answer 3

Well show me what you would do for the first one and I'll lead you to the right direction.

Answer 4

Do the exponents then multiply. Follow BEDMAS, have you heard of that?

Answer 5

yeah. I know pedmas(:
I just don't understand. Do you add the exponents?

Answer 6

\[\huge (a^n)^m =a ^{nm}\]

Answer 7

\[\huge a^na^m=a ^{n+m}\]

Answer 8

So first lets do the exponents and we'll work on multiplying after :)

Answer 9

so it'd be b^9 and b^5?

Answer 10

No look at what I wrote, \huge (a^n)^m =a ^{nm}

Answer 11

\[\huge (a^n)^m =a ^{nm}\]

Answer 12

When it's close like that, it means multiplying.

Answer 13

okay so you'd multiply 4 by 5 and 3 by 2?

Answer 14

Correct!

Answer 15

okay so b^20 and b^6 (:

Answer 16

Correct so now we have,

\[\huge b ^{20} \times b ^{6} \implies b ^{20+6}\]

Answer 17

oh! so b^26!! (:

Answer 18

Yup, does that make sense now?

We used these two properties \[\huge (a^n)^m =a ^{nm}\]

and \[\huge a^na^m=a ^{n+m}\]

Answer 19

The next question, just do it as you would a normal fraction, don't like the variable (p) scare you :P

Answer 20

yeah that makes sense(: and okay, so you'd subtract the top two numbers? but the bottom two would have to stay the same, so does that make p 5?