What is the standard form of an equation for a line that has a slope of -4/5 and passes through the point (2, -10)? 6x + 5y = -38 4x + 5y = -42 4x + 7y = -62 -4x + 5y = -58
So recall that the general form of a line is\[y=mx+b\]where m is the slope, and b is the y-intercept, alright, now also recall that to find the equation of a line given a point and a slope, you need to use the point-slope-formula which looks like this\[y-y_1=m(x-x_1)\]where m is again, your slope, and the point\[(x_1,y_1)\]is the point that you want the line to go through
Standard form is just moving all the variables to one side of general formula, and making sure there are no fractions
and ..... that the first one is the x part and that its not negative
Oh yeah, dangit, i forgot about that part of the rule, such a simple thing that you get used to i guess
4 years ago, taking a test ... got it wrong cuase of that simple rule :)
Ouch, i probably would have made the same mistake, and cried about it
4x+5y=-42
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The slope calculation wasn't necessary since the problem gave it to you, but yes, you definitely got the correct answer, great job
thank you
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