In the month of October, the population of a species of fish in a river increased by a factor of 1.05 every day. The function below shows the number of fish in the river f(x) after x days: f(x) = 100(1.05)x Which of the following is a reasonable domain for the function? 0 ≤ x ≤ 100 0 ≤ x ≤ 31 All positive integers greater than 100 All positive integers less than 100
@NeedHelpQuick546
What is the smallest possible value for f(x)? What is the greatest possible value for f(x)?
@nelsonjedi so b, right?
because 30 x 1.05 is 31.25
x has to be a positive number greater than zero because it begins on the first day of October, Thus if x is greater then 0,,,then f(x) has to be what?
so, yes
It is not b
What if a made x= .001..what would f(x) be?
well it says greater than OR equal to so it could be 0, therefore, it is b
You are looking at x we need to figure f(x)...So if x = .01 then f(x) = 100(1.05)(.01)
..... please, do continue, because now i'm a little confused
Ok x in the function represents the number of days correct.
yea
f(x) represents the number of fish,
The function should be \[\Large f(x) = 100(1.05)^x\] and not \[\Large f(x) = 100(1.05)(x)\]
yes
so, from all of this, i am now thinking its either D or A
We need to determine the domain of f(x).(The number of fish)
Can the number of days ever be 0?
ok
Can it?
yes
How can it be 0?
o days pass
Look at the equation..how many fish do you think are in the lake when we start?
100
Bingo..and is that number going to get bigger or smaller?
...ok i see your point
never 0 because it would make the population 0 in the long run of the equation
that would be true IF the equation were \[\Large f(x) = 100(1.05)(x)\] but the equation is \[\Large f(x) = 100(1.05)^x\]
@nelsonjedi
oh yea
@jim_thompson5910 so it is A?
hint: it has to do with October
My apologies I did not read the question correctly I was trying to solve the range...my bad.
lol its ok
and yea it was B the entire time lol
:-}
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