Geometric Sequence help anyone? List the next four terms of a geometric sequence with t1 = 4 and tn = -3tn-1. A. 12, 36, 108, 324 B. 12, 36, 48, 60 C. -12, 36, -108, 324 D. -12, 36, -48, 60 *If you'd rather walk me through the steps versus giving me the answer I'd appreciate that also!
"tn = -3tn-1" is really written \[\Large t_{n} = -3t_{n-1}\] I'm assuming
I'm still confused on how I go about solving this problem
If that assumption is correct, it means that the nth term \(\Large t_{n}\) is found by multiplying the previous term \(\Large t_{n-1}\) by -3
t1 is the first term t1 = 4 so the first term is 4
t2 is the second term you find t2 by multiplying the first term (t1) by -3 because of that rule that defines the nth term
so what is t2?
In other words, \[\Large t_{2} = -3*t_{1}\] what is \(\Large t_{2}\) ?
what is the value of t alone again? 4?
t has no value but when we say t1, t2, t3, etc etc...we're talking about the first term, second term, third term, etc etc...
initially, we are given \[\Large t_{1} = 4\] this is the first term
How do I find the second term? I'm sorry, it's been a long day my brain is working slow
you multiply -3 by the previous term to get the next term
that's exactly what this rule means \[\Large t_{n} = -3t_{n-1}\]
\(\Large t_{n}\) is the nth term \(\Large t_{n-1}\) is the term just before the nth term (the previous term of the nth term)
Oh okay, that makes more sense!
I think I got it from here, thank you so much for your help!
you're welcome
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