Question

please help

Answer 1

what????

Answer 2

Simple, subtract that pesky 64 to the other side since we want to solve for the variable X, then, you take the inverse operation of raising something to the second power, which is taking the second root, or in other words,\[(x^2)^{\frac{ 1 }{ 2 }}=(-64)^{\frac{ 1 }{ 2 }}\]

Answer 3

and you should recall that you can't take the square root of a negative number, therefore there is no solution

Answer 4

64 to both sides which gives you:
x^3=64 then you take the cuibc root of each side...

answer is x=4

Answer 5

no einstien he wrote it wrong its x^2

Answer 6

x=8i,-8i

I think it is C.

Answer 7

*she

PS I'm not einstein...It's just a pic

Answer 8

And even if trollface didn't change it, your equation should have been,\[x^3=-64\rightarrow x=-4\]

Answer 9

whos babe???

Answer 10

x^(2)+64=0

Since 64 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 64 from both sides.
x^(2)=-64

Take the square root of both sides of the equation to eliminate the exponent on the left-hand side.
x=+- sqrt(-64)

Pull all perfect square roots out from under the radical. In this case, remove the 8i because it is a perfect square.
x=+-8i

First, substitute in the + portion of the \ to find the first solution.
x=8i

Next, substitute in the - portion of the \ to find the second solution.
x=-8i

The complete solution is the result of both the + and - portions of the solution.
x=8i,-8i

Hope this helps. :)

Answer 11

LOL i saw that comment before you removed it Kx2bay, you can't hide it from me

Answer 12

correction, @Blank nailed it , so answer is D no solution

Answer 13

Proof: http://www.wolframalpha.com/input/?i=x%5E2+%2B+64+%3D+0

Answer 14

my secondary proof :)

Answer 15

There is only complex solutions. I believe that it is D.