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OpenStudy (anonymous):
\[\huge \log7\log2\log \pi ^{x}\]
It vanishes when x is
OpenStudy (anonymous):
(a) (pi)^2
(b)4
(c)49
(d)None of these
OpenStudy (shadowlegendx):
@hartnn <3
random231 (random231):
all bases are 10? O.o
OpenStudy (anonymous):
\[\log _{7}\log _{2}\log \pi^x ~ or ~ \log7\log2\log \pi ^x\]
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OpenStudy (anonymous):
That's what i think so That's the exact question given
No more ore less info
hartnn (hartnn):
what does "it vanishes" mean ?
ganeshie8 (ganeshie8):
becomes 0
OpenStudy (anonymous):
Becomes 0
OpenStudy (anonymous):
I wonder if you're taking the limit.
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random231 (random231):
none from the options!
random231 (random231):
if all the bases are 10
hartnn (hartnn):
\(x \log (49\pi ) = 0\)
x needs to be 0 then
hartnn (hartnn):
sorry, 14pi
Miracrown (miracrown):
So these seem multiplied to me rather than nested
so...
|dw:1401531299336:dw|
That raises an interesting issue
if you can have a logarithm with an irrational base. But obviously you can because "e" is irrational and that's the so-called natural logarithm. If you have no idea what I am saying here, ignore it. It's not that important