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Mathematics 8 Online
OpenStudy (thomas5267):

MEDALS! Question 8 without using angle sum identities. This is a screening test for a summer course for linear algebra in Hong Kong University. I was lucky as I thought that they would ask questions on trigonometry so I memorised the angle sum identities in the last minute. I think I got this right and I am curious on how to do question 8 without the identities.

OpenStudy (thomas5267):

Question 8:

OpenStudy (anonymous):

@BSwan

OpenStudy (anonymous):

why dnt you type a question at once xD :'(

OpenStudy (anonymous):

question 1 \(\sum_{n=1}^{n} (n+1) 2^{n-1}=n2^n\) by induction :- \(\color{red}{\text {STEP 1:-}}\) for n=1 2=2 its correct \(\color{red}{\text {STEP 2 :-}}\) assume its true for k \(\sum_{k=1}^{k} (k+1) 2^{k-1}=k2^k\) \(\color{red}{\text {STEP 3 :-}}\) show its true for k+1 :P can u do it ?

OpenStudy (anonymous):

the question is to evaluate sin(p+q) why would you wanna go long way though

OpenStudy (anonymous):

@BSwan he wants question 8 :P

OpenStudy (anonymous):

sorry for the wasted efforts xD

OpenStudy (anonymous):

O.O

OpenStudy (anonymous):

i hate u @aajugdar

OpenStudy (anonymous):

whaaa he mentioned he wants question 8 xD you didnt read

OpenStudy (thomas5267):

I finally got question 6 right after three trials. *sigh* Wasted quite a lot of time... :(

ganeshie8 (ganeshie8):

haha u gave right answer to a wrong question @BSwan :P

OpenStudy (thomas5267):

I mean in the test.

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

its my bad i dint read lol

OpenStudy (anonymous):

so stil wanna 8 ?

OpenStudy (anonymous):

@BSwan he wants to solve it without using trigonometry

OpenStudy (anonymous):

andd i hv no clue why o_o

OpenStudy (thomas5267):

Yep. I want to know how people can solve this without the identity.

OpenStudy (thomas5267):

I was lucky as I memorised the identity in the last minute (literally five minutes before the test). I just want to know how others can solve it.

OpenStudy (anonymous):

wew ! |dw:1401549520202:dw|

ganeshie8 (ganeshie8):

so the bottom triangle is a 3,4,5 triangle

OpenStudy (thomas5267):

I think the tricky bit is how to draw a triangle with p+q as one of the angles.

OpenStudy (anonymous):

is m parallel to f ? |dw:1401549742942:dw|

OpenStudy (thomas5267):

But not everyone in the test knows the identity so there must be a way solving it without using the identity. (ah... I know it is faulty logic but I just want the answer lolololol)

ganeshie8 (ganeshie8):

yes @BSwan there is no harm in constructing a parallel line to f, its perfectly valid

OpenStudy (anonymous):

:D |dw:1401549900070:dw|

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