Ask your own question, for FREE!
Chemistry 12 Online
OpenStudy (highschoolmom2010):

calculate the enthalpy change *see attachment*

OpenStudy (highschoolmom2010):

OpenStudy (ipwnbunnies):

Ok, cool. So we're looking for the enthalpy change from solid to a gas.

OpenStudy (ipwnbunnies):

From the pic, you can easily see that go to from ice to liquid water, there is an enthalpy change of +6 kJ.

OpenStudy (ipwnbunnies):

However, for the top one, they give you the enthalpy change of a gas to a liquid. So, the enthalpy change from going from liquid form to gas form will be the opposite of the number. c: To get the total, add the two enthalpies you got up.

OpenStudy (highschoolmom2010):

i dont understand what enthalpy is lol

OpenStudy (ipwnbunnies):

Enthalpy is a fancy word for how much heat was exchanged lol. So, you would expect enthalpy to be positive when going from a solid to a liquid. Or a liquid to a gas.

OpenStudy (highschoolmom2010):

so in this case it is positve bc we are going from solid to gas

OpenStudy (ipwnbunnies):

Mhm.c:

OpenStudy (highschoolmom2010):

so would i have to do -285.9 kJ+6.0 kJ

OpenStudy (ipwnbunnies):

Nope. Look at the picture, the reaction goes from a gas to a liquid, that's -285.9 kJ. So, to go from liquid water to the gas, you need 285.9 kJ. Now, you can add the two enthalpy changes for the total change.

OpenStudy (highschoolmom2010):

so -285.9 kJ+ 285.9 kJ+6?

OpenStudy (ipwnbunnies):

Nuuu. We're not using the -285.9 kJ. That was just to get the +285.9 kJ. We just want the enthalpy needed to from from liquid to gas.

OpenStudy (highschoolmom2010):

ergh ok so 285.9 kJ+6.0 kJ?

OpenStudy (ipwnbunnies):

Mhm. c:

OpenStudy (highschoolmom2010):

thank heavens so it is 291.9 kJ

OpenStudy (ipwnbunnies):

Mhm.

OpenStudy (highschoolmom2010):

@iPwnBunnies ok it says +291.9 is wrong........

OpenStudy (ipwnbunnies):

Ugh, are you srs. .-. Sorry. >.<

OpenStudy (ipwnbunnies):

I'm not sure how that's wrong. Do you have to include the units too?

OpenStudy (highschoolmom2010):

ill screenshot what it says

OpenStudy (highschoolmom2010):

OpenStudy (ipwnbunnies):

That really makes no sense. .-. If you have another shot, try the other positive one. Sorry about this. DX

OpenStudy (highschoolmom2010):

its ok at least u tried

OpenStudy (highschoolmom2010):

@iPwnBunnies i think it wants me to do -285.9kJ+6kJ

OpenStudy (ipwnbunnies):

Ugh, I really don't know. I don't know why. .-. You're going from a liquid to a gas, not a gas to a liquid.

OpenStudy (highschoolmom2010):

https://answers.yahoo.com/question/index?qid=20131106144122AA4EkOs even shows my answer right.....

OpenStudy (ipwnbunnies):

.-.

OpenStudy (somy):

the most easy way to remember is enthalpy change of reaction = product - reactant ur equation is \[H _{2}O \rightarrow H _{2} + 1\div2 O _{2}\] the tricky part is this

OpenStudy (somy):

look at it very carefully in first equation they are showing that from H2 GAS and O2 GAS u get water LIQUID originally in your equation water SOLID is broken to H2 GAS and O2 GAS that means u do not need liquid, also that means the equation of 'from H2 GAS and O2 GAS u get water LIQUID' and enthalpy change -285.9 is reverse of what you need, meaning if u switch places it's gonna be water LIQUID break down to H2 GAS and O2 GAS and of course enthalpy change will be with opposite sign thus +285.9 what does this new equation show? it shows Enthalpy change of formation of H2 and O2 gas from LIQUID water now you have value for your product side lets go to reactant side in original equation, its water SOLID right? ok, moving on to the next equation in next equation its turning from from water SOLID to water LIQUID and enthalpy change is +6 again u do NOT need water liquid, thus switch places now its gonna be turning from water LIQUID to water SOLID and enthalpy change will by with opposite sign thus -6 if u notice here, from liquid to solid water is basically enthalpy change of Formation of solid water right? so now u have ur reactant side also finally use the formula \[\Delta H = product - reactant \] thus = +285.9 - (-6) = +291.9 kj hope its clear now :D @iPwnBunnies @highschoolmom2010

OpenStudy (highschoolmom2010):

but it still says that my answer was wrong @Somy

OpenStudy (somy):

@highschoolmom2010 where is that question from?

OpenStudy (highschoolmom2010):

my chemistry assignment i did it and i was told to see why i got it wrong and i dont see how

OpenStudy (highschoolmom2010):

OpenStudy (somy):

so what's the answer supposed to be? @highschoolmom2010

OpenStudy (highschoolmom2010):

im not sure i keep getting +291.9 kJ

OpenStudy (somy):

yeah but what is the right answer @highschoolmom2010

OpenStudy (somy):

is the answer -279.9 kJ ? coz this one also does make sense

OpenStudy (highschoolmom2010):

i tried doing -285.9+6 also but was unsure which way to to it

OpenStudy (somy):

no, the thing is that i even tried Hess cycle and it gave me same answer @highschoolmom2010

OpenStudy (highschoolmom2010):

so im confused on which one you are sating is correct.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!