Question

Suppose

Answer 1

sorry... can't help

Answer 2

40.08+16.00*100?

Answer 3

@Destinymasha how do i do this?

Answer 4

What was the first part of it? "Suppose a similar experiment was performed?"

Answer 5

http://classroom.synonym.com/calculate-theoretical-percent-2826.html read up.

Answer 6

that's just what it say's there isn't a first part

Answer 7

where does the 4 come from in that reading? does it come from the sulfate?

Answer 8

You mean with the 4 * 16?

Answer 9

yes

Answer 10

CuSO4. That means one copper atom, one sulfer atom, and 4 oxygen atoms are combined. 16 grams=1 mole of oxygen. So one mole of O4=64 (16*4)

Answer 11

@Ash90 @halorazer answered your question

Answer 12

@lilcece mine is calcium oxide he was talking about copper sulfate

Answer 13

oh

Answer 14

lol it's okay

Answer 15

CaO is calcium oxide.

Answer 16

Use what I gave you above to calculate the theoretical percentage. I will not do it for you. At least try.

Answer 17

i'll do it but let me know if it's right
okay so i got 40.08+16.00=56.08*2=112.16/40.08=2.798?

Answer 18

No. Because it is a percentage, the percentages of Ca and O must add up to 1.
40.1 (I round to the tenths) + 16.0 (rounding, again) =56.1 grams of CaO in 1 mole.
Out of the 56.1 grams of CaO, Calcium (Ca) accounts for 40.1 of it.
40.1/56.1=0.714795009
Multiply by 100 to get it as a percentage.
71.4795009%
Since there's no number in the original question, we can't tell how many significant figures are used, so because we went to the tenths in our rounding of the CaO mass, we'll go to tenths here.
71.5% calcium in calcium oxide.

Answer 19

oh okay so i'm supposed to divide 40.01 over 56.1 rather then what i did up top

Answer 20

Yes.