Topic: Base e and Natural Logarithms
Directions: Solve each equation or inequality round to nearest ten thousandth
Problem: e^5x+434

Question

Topic: Base e and Natural Logarithms
Directions: Solve each equation or inequality round to nearest ten thousandth
Problem: e^5x+4>34

jdoe0001 · Answer

have  you covered logarithms yet?

anonymous · Answer

@jdoe0001 Yes its the end of the year and she wants us to refresh our memory so I need to see the steps

jdoe0001 · Answer

$\bf e^{5x}+4>34\quad ?$

jdoe0001 · Answer

or is it $\bf e^{5x+4}>34\quad ?$

anonymous · Answer

@jdoe0001 Your first guess

imstuck · Answer

Subtract 4 from both sides and get $$e ^{5x}>30$$Now take the natural log (ln) of both sides.  The natural log of $$e ^{5x}$$, that is, ln(e^5x) is just 5x.  So 5x > 3.4012 (that's what you get when you take the ln(30)).  Now divide both sides by 5.  So x = .680