How many moles of aluminum metal are needed to produce 3.33 moles of aluminum chloride?
could someone show me how to do it
@Destinymasha
Do you know the equation for the reaction or no?
no I totally don't even no where to start
2Al + 3Cl2 -> 2AlCl3 The numbers in front of the substances are mole ratios. So for every 2 moles of Aluminum there are 3 moles of Cl2. And for every 2 moles of Aluminum there are 2 moles of AlCl3. Just put in 3.33 in front of the AlCl3, and because the mole ratio for Al to AlCl3 is 1:1 Therefore because there are 3.33 moles of AlCl3, that means there must be 3.33 moles of Al as well.
Sorry it took so long. I went through the steps to find moles of Cl2 and then went back and realized it asked for aluminum xD
ok its cool bro but is that for every one
For every one what?
how did u get that equation
2Al + 3Cl2 -> 2AlCl3 Well you can't get Aluminum Chloride (2AlCl3) without 2Al and 3Cl2. Think of it this way. You know about the distributive property in math? Where you multiply the number outside of the parentheses by the number/s inside? Al is the same as Al1. 2(Al1) + 3(Cl2) -> 2(Al1Cl3) Al2 + Cl6 -> Al2Cl6 It wouldn't work as Al + Cl3 -> AlCl3 because Cl3 does not exist in the natural world, only Cl2. But when it's in a substance like AlCl3, it does exist. It's weird, I know.
so I just combine the 2 to get my answer
What do you mean?
do you combine the two equations
No, you don't. Usually they will give you the equation with the question, unless earlier in the year they expected you to memorize a bunch of chemical equations.
ok thank u so much for ur help man uve been very helpful all day and I appreciate it
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