Question

Please help, will award a metal for first to answer correctly

Answer 1

@jinxhead20 @sammixboo

Answer 2

Question is in attachment

Answer 3

Let's start with the maximum/minimum part:
Notice that this is a sine function. It's going to begin exactly between its maximum and minimum points.

It's in the form \[a \sin(k x)\] as you can see. a is the amplitude of the function; this means that the maximum and minimum points will be +/-a from the y-intercept, which you can find by plugging in t=0.

Answer 4

So how do I solve this?

Answer 5

What equation do I type to solve, I don't know I am confused and our lessons are only one paragraph.

Answer 6

It is B

Answer 7

IS B CORRECT, ALSO I HAVE ANOTHER QUESTION

Answer 8

Yes, it is B. I was trying to draw it out and explain it, but you got it while I was typing :p Good job.

Answer 9

This is the other question, I don't know how to solve it even though it is similar because it is asked in a different style

Answer 10

I think it is 5 if you plug it in for zero, but I am not sure if 5 is the answer

Answer 11

Note that this deals with a cosine, not a sine, curve. It's going to start at (0,1) instead of (0,0).

You should be able to just plug in t=9 to get how high the tide is after 9 hours.

Answer 12

Give me a minute can you?

Answer 13

(Sorry, when I said the stuff about (0,1) and (0,0) I was talking about the base functions of cos(x) and sin(x), not the actual problem at hand)

Answer 14

Okay so how do I solve this problem, I plugged it in and got 2 somehow

Answer 15

Ha, I did the same thing as I was trying to solve it. Simple math error inside the cosine function:

(pi/6) * t
Plug in t=9.
(pi/6) * 9
This becomes
\[\frac{\pi}{6}*\frac{9}{1}\]
I'm pretty sure we both got rid of the 6 entirely and said it multiplied to 3pi. This is not the case. 9/6 simplifies to 3/2, so:
3pi/2

should be inside the cosine, not 3pi.

Answer 16

So what is next, how many hours is it?

Answer 17

There are still 9 hours. What I'm saying is that, if I'm not mistaken, your math looked like:
3cos(pi/6 * t) + 5
3cos(pi/6 * 9) + 5
3cos(3pi) + 5
3*-1 + 5
-3 + 5
2

If you look back at it, you multiplied wrong early on. The math should be:
3cos(pi/6 * t) + 5
3cos(pi/6 * 9) + 5
3cos(3pi/2) + 5
and simplified from there.

Answer 18

The answer is 5, also I have these two more questions and we are done

Answer 19

You here?

Answer 20

Yes, 5 is the answer, yes I'm here.

For the top one, I got an answer that wasn't listed. Can you type out exactly what the expression is?

Answer 21

Try the second one and we will get back to it

Answer 22

\[(\sin(\theta)-\cos*(\theta))^2)-(\sin(\theta)+\cos*(\theta))^2)\]

Answer 23

Alright

Let's start with g(x) and h(x).
For g(x), it's plain to see that its lowest value is 6.
For h(x), it's also pretty obvious that the lowest value is 5.

Now, for f(x), I'll sketch a graph. Just so you know, the stuff inside of the trig function only changes how compressed/stretched or how shifted to the left/right it is. Because of this, I'm just going to sketch out -4sin(x)+11: