Question

How do you find the volume of a sphere?

Answer 1

4/3(pi)(r)cubed

Answer 2

\[V=\frac{ 4 }{ 3 } \pi r ^{3}\]

Answer 3

^ and ^^ are correct

Answer 4

what do i plug in ?

Answer 5

What information does it give you?

Answer 6

well we dont know the measurements or anything so could you please gives us some

Answer 7

The Radius is 15cm

Answer 8

well r=radius

Answer 9

so plug that number into the equation where r is and solve

Answer 10

do i do 15*pi

Answer 11

Exponents first, right Jon?
So \[r ^{3}\]

Answer 12

yes which would be \[15^{3}\]

Answer 13

So 15*15*15 = ?

Answer 14

yes @Quuen_Si please solve that for now

Answer 15

i got 3375

Answer 16

\[3375\pi\]

Answer 17

What's your answer?

Answer 18

yes so multiply 3375 by 4/3 first

Answer 19

Am I doing this right Jon? Correct me if I'm wrong.

Answer 20

i recommend multiplying by the fraction first to get the most accurate answer

Answer 21

Oh, I always did the fraction last, and in a different way. I've always done the number*pi first, then the fraction.

Answer 22

well you get pretty much the same answer but some people use 3.14 instead of all of pi... thats why i recommend using the fraction first because it doesnt mess up the rest of the equation

Answer 23

btw @_Michaeld22 danni is on

Answer 24

Lol yeah, I saw.
So @Quuen_Si, what answer did you get for 4/3*3375

Answer 25

4500

Answer 26

Yes, now 4500*pi, or 3.14, whichever you prefer.

Answer 27

yes now multiply by full pi or 3.14 ^

Answer 28

round final answer if need be

Answer 29

14130

Answer 30

Yup. Final answer is: \[14130(units)^{}\]

Answer 31

units cubed

Answer 32

Sorry that was supposed to be units cubed

Answer 33

Thanks for helping Jon. Lol.

Answer 34

NO thank you

Answer 35

im off now

Answer 36

you can do volume of cylinder = the volume under the cone

Answer 37

???

Answer 38

-*

Answer 39

:)

Answer 40

ok...

Answer 41

wut

Answer 42

u know what i mean dont u !!

Answer 43

dan please stop i keep getting notifications and it is quite annoying...

Answer 44

ok sry

Answer 45

thanks... and yes i know what you mean but it is a longer process

Answer 46

integration way

Answer 47

ya... ok im gonna leave this question now...

Answer 48

ok