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Mathematics 23 Online
OpenStudy (rane):

how can i prove these?

OpenStudy (rane):

q' 10right at the top

OpenStudy (anonymous):

|dw:1401615644483:dw|

OpenStudy (anonymous):

so those ppl dnt know the altenate xD poor lolz it like prove the alternate thm

OpenStudy (anonymous):

maybe he/she is still in school

ganeshie8 (ganeshie8):

everything here is a postulate, and not a theorem

OpenStudy (anonymous):

@aajugdar its not for school , if it was scholl then its enough to say alternate :P

OpenStudy (anonymous):

anyway @rani u have the steps just write the postulates that justify them

ganeshie8 (ganeshie8):

Try below : (i) - Same side interior angles theorem* (ii) - linear pair angles addup to 180 (iii) - By substitution (iv) - By subtraction property of equality

ganeshie8 (ganeshie8):

* we call it theorem even though it is not

OpenStudy (anonymous):

this thing is freaks me out xD the alternate thm prove all of the above so why i use all of them to prove it xD

ganeshie8 (ganeshie8):

yes you need to call one of them a `postulate`, then u can use it to prove everything else....

OpenStudy (anonymous):

without alternate i wont have Same side interior angles

ganeshie8 (ganeshie8):

it doesnt matter which one u call a `postulate`

OpenStudy (anonymous):

which make no sense to me

OpenStudy (rane):

guys can one someone just explain it to me, I'm studying for my exam... I'm in hurry if u guys don't mind..

ganeshie8 (ganeshie8):

You can take any one of below result as `postulate` and prove the remaining stuff : 1) corresponding angles are equal 2) alternate interior angles are equal 3) alternate exterior angles are equal 4) same side interior angles are supplementary ...

OpenStudy (anonymous):

u can use the parallel axiom as a postulate but the interior thingy xD what im saying ... @ganeshie8 is that there is many proofs u can start with but that book thing why they teach wrong steps :O

OpenStudy (rane):

Alright! so from beginning how can i respond to this question or any of these ?

OpenStudy (anonymous):

|dw:1401616404004:dw| \[\tan i= \frac{ AC }{ AB }=\frac{ BD }{ DC }=\tan i'\]donc\[i=i'\]or \[a=i+\pi/2=i'+\pi/2=a'\]

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