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Chemistry 11 Online
OpenStudy (anonymous):

I need help in this???

OpenStudy (anonymous):

The answer is already marked in the red box, my my question is: why??? why not C?

OpenStudy (aaronq):

\(NH_4NO_3\) can b separated into \(NH_4^+\) and \(NO_3^-\) for the nitrate ion, this needs to hold because the charge is negative one -1=N+(-2)*3, so N=+5 In \(N_2O\) the N atom is +1 so change from +5 to+1 is -4

OpenStudy (anonymous):

wait N2O

OpenStudy (anonymous):

I don't get the charge of N2O

OpenStudy (anonymous):

@aaronq

OpenStudy (aaronq):

O=-2, this needs to hold because its neutral, 0=-2+2N, N=+1

OpenStudy (anonymous):

Oooh ok and for NO3 it's going to be +6? for N?

OpenStudy (anonymous):

OooooOOOOoooo!!! Okayyy I got now!

OpenStudy (aaronq):

no, recall that there is an overall -1 charge on the ion. -1=N+3(-2), N=+5

OpenStudy (anonymous):

No no @aaronq I made a mistake there I did not see the negative charge (-1)

OpenStudy (somy):

@aarong from NH4+ to N2O its gonna be +4 change and from NO3- to N2O is gonna be -4 change is it like that? or am i getting it wrong?

OpenStudy (somy):

@aaronq

OpenStudy (aaronq):

yeah N in NH4^+ is -3, so to get to +1, you remove 4 electrons, hence a change of +4.

OpenStudy (somy):

thaaaaanks!!! @aaronq we get it now :D

OpenStudy (anonymous):

Now I got it 100% thank you :) @aaronq @Somy

OpenStudy (aaronq):

no problem guys!

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